★ Pass on Your First TRY ★ 100% Money Back Guarantee ★ Realistic Practice Exam Questions

Free Instant Download NEW 100-105 Exam Dumps (PDF & VCE):
Available on: https://www.certleader.com/100-105-dumps.html


Cisco 100-105 exam dumps are composed by Exambibles exceptional professionals who have a good deal of encounter in compiling the particular Cisco 100-105 exam demos. They are numerous kinds of Cisco 100-105 analyze questions and answers which will appear inside the real analyze. A lot of candidates have got passed the particular Cisco Cisco exam since we all started. Exambible guarantees you substantial quality along with great benefit which guarantee you the passing score.

2021 Mar 100-105 practice test

Q71. - (Topic 5) 

Refer to the exhibit. 

Serial 0/0 does not respond to a ping request from a host on the FastEthernet 0/0 LAN. How can this problem be corrected? 

A. Enable the Serial 0/0 interface. 

B. Correct the IP address for Serial 0/0. 

C. Correct the IP address for FastEthernet 0/0 

D. Change the encapsulation type on Serial 0/0 

E. Enable autoconfiguration on the Serial 0/0 interface 

Answer:

Explanation: 

Serial 0/0 interface is administratively down therefore, you will have to run the "no shutdown" command to enable the interface for data. 


Q72. - (Topic 3) 

Which of the following IP addresses are valid Class B host addresses if a default Class B mask is in use? (Choose two.) 

A. 10.6.8.35 

B. 133.6.5.4 

C. 192.168.5.9 

D. 127.0.0.1 

E. 190.6.5.4 

Answer: B,E 

Explanation: 

The IP addresses 133.6.5.4 and 190.6.5.4 are both valid Class B addresses when a default mask is in use. The Class B default mask is 255.255.0.0 and the range of valid addresses is 128.0.0.0-

191.255.255.255. 

The IP address 10.6.8.35 is a Class A address. The Class A default mask is 255.0.0.0 and 

the range of valid addresses is 1.0.0.0 - 127.255.255.255, with the exception of the range 

127.0.0.1 - 127.255.255.255, which is reserved and cannot be assigned. 

The IP address 192.168.5.9 is a Class C address. The Class C default mask is 

255.255.255.0 and the range of valid addresses is 192.0.0.0 - 223.255.255.255. 

The IP address 127.0.0.1 is a Class A address, but it comes from a reserved portion that 

cannot be assigned. 

The range 127.0.0.1 - 127.255.255.255 is used for diagnostics, and although any address 

in the range will work as a diagnostic address, 127.0.0.1 is known as the loopback address. 

If you can ping this address, or any address in the 127.0.0.1 - 127.255.255.255 range, then 

the NIC is working and TCP/IP is installed. The Class A default mask is 255.0.0.0 and the range of valid addresses is 1.0.0.0 - 127.255.255.255, with the exception of the range 

127.0.0.1 - 127.255.255.255, which is reserved and cannot be assigned. 


Q73. - (Topic 2) 

A switch receives a frame on one of its ports. There is no entry in the MAC address table for the destination MAC address. What will the switch do with the frame? 

A. drop the frame 

B. forward it out of all ports except the one that received it 

C. forward it out of all ports 

D. store it until it learns the correct port 

Answer:

Explanation: 

Understanding this concept is prime for understanding that when switch receives the data frame from the host not having the MAC address already in the MAC table, it will add the MAC address to the source port on the MAC address table and sends the data frame. If the switch already has the MAC address in its table for the destination, it will forward the frame directly to the destination port. If it was not already in its MAC table, then they frame would have been flooded out all ports except for the port that it came from. 


Q74. - (Topic 1) 

Which OSI layer header contains the address of a destination host that is on another network? 

A. application 

B. session 

C. transport 

D. network 

E. data link 

F. physical 

Answer:

Explanation: 

Only network address contains this information. To transmit the packets the sender uses network address and datalink address. But the layer 2 address represents just the address of the next hop device on the way to the sender. It is changed on each hop. Network address remains the same. 


Q75. - (Topic 7) 

Which route source code represents the routing protocol with a default administrative distance of 90 in the routing table? 

A. S 

B. E 

C. D 

D. R 

E. O 

Answer:

Explanation: 

SStatic EEGP DEIGRP RRIP OOSPF 

Default Administrative distance of EIGRP protocol is 90 then answer is C 

Default Distance Value TableThis table lists the administrative distance default values of the protocols that Cisco supports: 

Route Source Default Distance Values 

Connected interface 0 Static route 1 Enhanced Interior Gateway Routing Protocol (EIGRP) summary route 5 External Border Gateway Protocol (BGP) 20 Internal EIGRP 90 IGRP 100 OSPF 110 Intermediate System-to-Intermediate System (IS-IS) 115 Routing Information Protocol (RIP) 120 Exterior Gateway Protocol (EGP) 140 On Demand Routing (ODR) 160 External EIGRP 170 Internal BGP 200 Unknown* 255 


Renew 100-105 free practice exam:

Q76. DRAG DROP - (Topic 1) 

On the left are various network protocols. On the right are the layers of the TCP/IP model. Assuming a reliable connection is required, move the protocols on the left to the TCP/IP layers on the right to show the proper encapsulation for an email message sent by a host on a LAN. (Not all options are used.) 

Answer: 


Q77. - (Topic 3) 

Which IP address is a private address? 

A. 12.0.0.1 

B. 168.172.19.39 

C. 172.20.14.36 

D. 172.33.194.30 

E. 192.169.42.34 

Answer:


Q78. - (Topic 3) 

Which IOS command is used to initiate a login into a VTY port on a remote router? 

A. router# login 

B. router# telnet 

C. router# trace 

D. router# ping 

E. router(config)# line vty 0 5 

F. router(config-line)# login 

Answer:

Explanation: 

VTY ports are telnet ports hence command B will initiate login to the telnet port. 


Q79. - (Topic 5) 

The following commands are entered on the router: 

Burbank(config)# enable secret fortress 

Burbank(config)# line con 0 

Burbank(config-line)# login 

Burbank(config-line)# password n0way1n 

Burbank(config-line)# exit 

Burbank(config)# service password-encryption 

What is the purpose of the last command entered? 

A. to require the user to enter an encrypted password during the login process 

B. to prevent the vty, console, and enable passwords from being displayed in plain text in the configuration files 

C. to encrypt the enable secret password 

D. to provide login encryption services between hosts attached to the router 

Answer:

Explanation: 

Certain types of passwords, such as Line passwords, by default appear in clear text in the configuration file. You can use the service password-encryption command to make them more secure. Once this command is entered, each password configured is automatically encrypted and thus rendered illegible inside the configuration file (much as the Enable/Enable Secret passwords are). Securing Line passwords is doubly important in networks on which TFTP servers are used, because TFTP backup entails routinely moving config files across networks—and config files, of course, contain Line passwords. 


Q80. CORRECT TEXT - (Topic 6) 

Answer: Router>enable 

Router#config terminal Router(config)#hostname Apopka 2) Enable-secret password (cisco10): Apopka(config)#enable secret cisco10 3) Set the console password to RouterPass: Apopka(config)#line console 0 Apopka(config-line)#password RouterPass Apopka(config-line)#login Apopka(config-line)#exit 4) Set the Telnet password to scan90: Apopka(config)#line vty 0 4 Apopka(config-line)#password scan90 Apopka(config-line)#login Apopka(config-line)#exit 5) Configure Ethernet interface (on the right) of router Apopka: The subnet mask of the Ethernet network 209.165.201.0 is 27. From this subnet mask, we can find out the increment by converting it into binary form, that is /27 = 1111 1111.1111 1111.1111 1111.1110 0000. Pay more attention to the last bit 1 because it tells us the increment, using the formula: Increment = 2place of the last bit 1 (starts counting from 0,from right to left), in this case increment = 25 = 32. Therefore: Increment: 32 Network address: 209.165.201.0 Broadcast address: 209.165.201.31 (because 209.165.201.32 is the second subnetwork, so the previous IP - 209.165.201.31 - is the broadcast address of the first subnet). -> The second assignable host address of this subnetwork is 209.165.201.2/27 Assign the second assignable host address to Fa0/0 interface of Apopka router: Apopka(config)#interface Fa0/0 Apopka(config-if)#ip address 209.165.201.2 255.255.255.224 Apopka(config-if)#no shutdown Apopka(config-if)#exit 6) Configure Serial interface (on the left) of router Apopka: Using the same method to find out the increment of the Serial network: Serial network 192.0.2.128/28: Increment: 16 (/28 = 1111 1111.1111 1111.1111 1111.1111 0000) Network address: 192.0.2.128 (because 8 * 16 = 128 so 192.0.2.128 is also the network address of this subnet) Broadcast address: 192.0.2.143 -> The last assignable host address in this subnet is 192.0.2.142/28. Assign the last assignable host address to S0/0/0 interface of Apopka router: Apopka(config)#interface S0/0/0 (or use interface S0/0 if not successful) Apopka(config-if)#ip address 192.0.2.142 255.255.255.240 Apopka(config-if)#no shutdown Apopka(config-if)#exit 7) Configure RIP v2 routing protocol: Apopka(config)#router rip Apopka(config-router)#version 2 Apopka(config-router)#network 209.165.201.0 Apopka(config-router)#network 192.0.2.128 Apopka(config-router)#end Save the configuration: Apopka#copy running-config startup-config Finally, you should use the ping command to verify all are working properly! 

Topic 7, Mix Questions