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2021 Nov ceh 312-50 pdf:

Q231. What is GINA? 

A. Gateway Interface Network Application 

B. GUI Installed Network Application CLASS 

C. Global Internet National Authority (G-USA) 

D. Graphical Identification and Authentication DLL 

Answer: D

Explanation: In computing, GINA refers to the graphical identification and authentication library, a component of some Microsoft Windows operating systems that provides secure authentication and interactive logon services. 


Q232. You want to know whether a packet filter is in front of 192.168.1.10. Pings to 192.168.1.10 don't get answered. A basic nmap scan of 192.168.1.10 seems to hang without returning any information. What should you do next? 

A. Use NetScan Tools Pro to conduct the scan 

B. Run nmap XMAS scan against 192.168.1.10 

C. Run NULL TCP hping2 against 192.168.1.10 

D. The firewall is blocking all the scans to 192.168.1.10 

Answer: C


Q233. You run nmap port Scan on 10.0.0.5 and attempt to gain banner/server information from services running on ports 21, 110 and 123. 

Here is the output of your scan results: 

Which of the following nmap command did you run? 

A. nmap -A -sV -p21,110,123 10.0.0.5 

B. nmap -F -sV -p21,110,123 10.0.0.5 

C. nmap -O -sV -p21,110,123 10.0.0.5 

D. nmap -T -sV -p21,110,123 10.0.0.5 

Answer: C


Q234. If an attacker's computer sends an IPID of 24333 to a zombie (Idle Scanning) computer on a closed port, what will be the response? 

A. The zombie computer will respond with an IPID of 24334. 

B. The zombie computer will respond with an IPID of 24333. 

C. The zombie computer will not send a response. 

D. The zombie computer will respond with an IPID of 24335. 

Answer: C


Q235. An attacker runs netcat tool to transfer a secret file between two hosts. 

Machine A: netcat -l -p 1234 < secretfile 

Machine B: netcat 192.168.3.4 > 1234 

He is worried about information being sniffed on the network. How would the attacker use netcat to encrypt the information before transmitting onto the wire? 

A. Machine A: netcat -l -p -s password 1234 < testfileMachine B: netcat <machine A IP> 1234 

B. Machine A: netcat -l -e magickey -p 1234 < testfileMachine B: netcat <machine A IP> 1234 

C. Machine A: netcat -l -p 1234 < testfile -pw passwordMachine B: netcat <machine A IP> 1234 -pw password 

D. Use cryptcat instead of netcat 

Answer: D

Explanation: Netcat cannot encrypt the file transfer itself but would need to use a third party application to encrypt/decrypt like openssl. Cryptcat is the standard netcat enhanced with twofish encryption. 


Renovate ceh exam 312-50 pdf:

Q236. On a default installation of Microsoft IIS web server, under which privilege does the web server software execute? 

A. Everyone 

B. Guest 

C. System 

D. Administrator 

Answer: C

Explanation: If not changed during the installation, IIS will execute as Local System with way to high privileges. 


Q237. Josh is the network administrator for Consultants Galore, an IT consulting firm based in Kansas City. Josh is responsible for the company's entire network which consists of one Windows Server 2003 Active Directory domain. Almost all employees have Remote Desktop access to the servers so they can perform their work duties. Josh has created a security group in Active Directory called "RDP Deny" which contains all the user accounts that should not have Remote Desktop permission to any of the servers. What Group Policy change can Jayson make to ensure that all users in the "RDP Deny" group cannot access the company servers through Remote Desktop? 

A. Josh should add the "RDP Deny" group into the list of Restricted Groups to prevent the users from accessing servers remotely. 

B. By adding the "RDP Deny" group to the "Deny logon as a service" policy, the users in that security group will not be able to establish remote connections to any of the servers. 

C. He should add the "RDP Deny" group to the "Deny RDP connections to member servers" policy. 

D. Josh needs to add the "RDP Deny" group to the "Deny logon through Terminal Services" policy. * 

Answer: D

New questions 

604. Which of the following countermeasure can specifically protect against both the MAC Flood and MAC Spoofing attacks? 

A. Configure Port Security on the switch 

B. Configure Port Recon on the switch 

C. Configure Switch Mapping 

D. Configure Multiple Recognition on the switch 

Answer: A


Q238. fter studying the following log entries, what is the attacker ultimately trying to achieve as inferred from the log sequence? 

1. mkdir -p /etc/X11/applnk/Internet/.etc 

2. mkdir -p /etc/X11/applnk/Internet/.etcpasswd 

3. touch -acmr /etc/passwd /etc/X11/applnk/Internet/.etcpasswd 

4. touch -acmr /etc /etc/X11/applnk/Internet/.etc 

5. passwd nobody -d 

6. /usr/sbin/adduser dns -d/bin -u 0 -g 0 -s/bin/bash 

7. passwd dns -d 

8. touch -acmr /etc/X11/applnk/Internet/.etcpasswd /etc/passwd 

9. touch -acmr /etc/X11/applnk/Internet/.etc /etc 

A. Change password of user nobody 

B. Extract information from a local directory 

C. Change the files Modification Access Creation times 

D. Download rootkits and passwords into a new directory 

Answer: C


Q239. Bill successfully executed a buffer overflow against a Windows IIS web server. He has been able to spawn in interactive shell and plans to deface the main web page. He fist attempts to use the “Echo” command to simply overwrite index.html and remains unsuccessful. He then attempts to delete the page and achieves no progress. Finally, he tires to overwrite it with another page in which also he remains unsuccessful. What is the probable cause of Bill’s problem? 

A. The system is a honeypot 

B. The HTML file has permissions of read only 

C. You can’t use a buffer overflow to deface a web page 

D. There is a problem with the shell and he needs to run the attack again 

Answer: B

Explanation: A honeypot has no interest in stopping an intruder from altering the “target” files. A buffer overflow is a way to gain access to the target computer. Once he has spawned a shell it is unlikely that it will not work as intended, but the user context that the shell is spawned in might stop him from altering the index.html file incase he doesn’t have sufficient rights. 


Q240. After studying the following log entries, how many user IDs can you identify that the attacker has tampered with? 

1. mkdir -p /etc/X11/applnk/Internet/.etc 

2. mkdir -p /etc/X11/applnk/Internet/.etcpasswd 

3. touch -acmr /etc/passwd /etc/X11/applnk/Internet/.etcpasswd 

4. touch -acmr /etc /etc/X11/applnk/Internet/.etc 

5. passwd nobody -d 

6. /usr/sbin/adduser dns -d/bin -u 0 -g 0 -s/bin/bash 

7. passwd dns -d 

8. touch -acmr /etc/X11/applnk/Internet/.etcpasswd /etc/passwd 

9. touch -acmr /etc/X11/applnk/Internet/.etc /etc 

A. IUSR_ 

B. acmr, dns 

C. nobody, dns 

D. nobody, IUSR_ 

Answer: C

Explanation: Passwd is the command used to modify a user password and it has been used together with the usernames nobody and dns.